How many ounces of each type of tea does the merchant use in the blend? Briefly describe the principles of scientific management and administrative management. What are the (a) period and (b) frequency? (c) The wavelength is 1.9 m what is the wave speed? A merchant blends tea that sells for $3.25 an ounce with tea that sells for $2.50 an ounce to produce 90 oz of a mixture that sells for $2.80 an ounce. The time for a particular point to move from maximum displacement to zero is 0.13 s. Assuming she can earn an 8% annual return on her investments how much will she need to save at the end of each of the next 20 years to accomplish her goal? A sinusoidal wave travels along a string. Elizabeth wants to have $500,000 saved for retirement in 20 years. The arrow reaches its maximum height in seconds. After how many seconds does the arrow reach it maximum height? Round to the nearest tenth of a second if necessary. What is the charge on a deuterium nucleus in units of qe = 1.6*10-19 C? h(t) = - 16t2 + 64t + 112 where t is the time in seconds. product production selling marketing societal marketing In the early universe and in stars, deuterium nuclei are produced from the combination of one proton and one neutron, with the release of a gamma ray. Henry Ford's philosophy was to perfect the Model T so that its cost could be reduced further for increased consumer affordability. Revenues, expenses, and withdrawals accounts, which are closed at the end of each accounting period are:Select one:a. Indeed, it can be demonstrated that for a projectile launched from height h, the angle at which the maximum range is achevied is given byĪnd indeed, by substituting u = 13.0 m/s and h = 1.80 m into the formula, we find Therefore we can infer an important thing: while for a projectile launched from the ground (h=0) the maximum range is achieved when the angle of launch is, this is not true for a projectile launched from a height h. We see from the previous parts that the angle that gives the maximum range is. We can solve the problem exactly in the same, replacing the previous angle with : Substituting t = 1.93 s, we find the range of the shot: Now, the horizontal distance travelled by the shot is given by We discard the former solution since it's negative, so the correct time is Which gives two solutions: t = -0.19 s and t = 1.93 s. Substituting y(t)=0, we solve the equation for t, to find the time at which the shot reaches the ground: G = 9.8 m/s^2 is the acceleration of gravity This can be found by analyzing the vertical motion only, using the equation: The speed of the frame S' with respect to frame S = v.Ġ\ \Rightarrow v>0." alt="\rm \Delta t'=\dfrac.\\\\Also, \ \Delta t,\ \Delta x>0\ \Rightarrow v>0." align="absmiddle" class="latex-formula">Īnd positive v means the velocity of the second frame S' is along the positive x-axis direction, i.e., to the right direction relative to the original frame S.įirst of all, we need to find the time it takes for the shot to reach the ground. In the second reference frame S', the two flashes are simultaneous, which means that the temporal interval of the event in this frame is To the right relative to the original frame.
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